A) 2h
B) 2 days
C) 2yr
D) 20 yr
Correct Answer: D
Solution :
1 electron has a charge of \[1.6\times {{10}^{-19}}C\] \[{{10}^{10}}\] electrons would have a charge of \[q=ne\] \[=1.6\times {{10}^{-19}}\times {{10}^{10}}=1.6\times {{10}^{-9}}C\] Thus, in 1 s, charge accumulated \[=1.6\times {{10}^{-9}}C\] So, time taken to accumulate 1C \[=\frac{1}{1.6\times {{10}^{-9}}}=0.625\times {{10}^{9}}\] \[=6.25\times {{10}^{8}}=s=173611\,h\] \[=7233\] days \[\approx 20\,yr\]
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