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DUMET Medical DUMET Medical Solved Paper-2010

  • question_answer
    The motion of a particle executing SHM in one dimension      is      described      by x = - 0.3 sin\[(t+\pi /4),\]where x is in metre and \[t\]in second. The frequency of oscillation in Hz is

    A)  \[3\]     

    B)  \[1/2\pi \]  

    C) \[\pi /2\]   

    D)  \[1/\pi \]

    Correct Answer: B

    Solution :

     We have \[x=-0.3sin\,(t-\pi /4)\] Comparing with the general equation \[x={{x}_{0}}\sin \,(\omega \,t+\phi )\] So, \[{{x}_{0}}=0.3,\,\,\omega =1,\phi =\pi /4\] Hence, \[2\,\pi f=1\] \[\Rightarrow \] \[f=1/2\pi \]


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