DUMET Medical DUMET Medical Solved Paper-2010

  • question_answer
    The average magnetic energy density of an electromagnetic wave of wavelength\[\lambda \] travelling in free space is given by

    A) \[\frac{{{B}^{2}}}{2\lambda }\]

    B) \[\frac{{{B}^{2}}}{2{{\mu }_{o}}}\]

    C) \[\frac{2{{B}^{2}}}{{{\mu }_{o}}\lambda }\]

    D) \[\frac{B}{{{\mu }_{o}}\lambda }\]

    Correct Answer: B

    Solution :

     Energy density of an electromagnetic wave is \[U=\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}+\frac{1}{2}\frac{{{B}^{2}}}{{{\mu }_{0}}}\] So, the magnetic energy density is \[\frac{{{B}^{2}}}{2{{\mu }_{0}}}\].


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