A) 3/5
B) 2
C) 1
D) 5/3
Correct Answer: C
Solution :
The internal energy of a gas is given by \[U=n{{C}_{V}}T\] Since, \[{{U}_{He}}={{U}_{{{H}_{2}}}}\] So \[{{n}_{He}}{{C}_{V}}{{T}_{He}}={{n}_{{{H}_{2}}}}{{C}_{V}}{{T}_{{{H}_{2}}}}\] For He. the value of Cy \[{{C}_{V}}=\frac{5}{2}R\] For H, the valve of \[{{C}_{V}}\] \[{{C}_{V}}-\frac{3}{2}R\] \[\therefore {{n}_{He}}\times \frac{3}{2}R\times 10T={{n}_{H}}\times \frac{5}{2}\times 6T\] or \[\frac{{{n}_{He}}}{{{n}_{H}}}=1\] or \[\frac{{{n}_{1}}}{{{n}_{2}}}=1\]
You need to login to perform this action.
You will be redirected in
3 sec
