A) \[\Delta E\]
B) \[\Delta E=\Delta H+\Delta {{n}_{g}}RT\]
C) \[\Delta E=\Delta H-\Delta {{n}_{g}}RT\]
D) \[\Delta E={{E}_{a}}+RT\]
Correct Answer: C
Solution :
From first law of thermodynamics, we have \[\Delta E=Q+W\] ... (i) Here, \[\Delta E=\] change in internal energy, \[=\Delta E\] Q = heat of the reaction \[=\Delta H\] W = work done \[=-P\Delta V\] (\[\because \]Reaction is endothermic.) \[=\Delta {{n}_{g}}RT\] Thus, Eq. (i) becomes \[\Delta E=\Delta H-\Delta {{n}_{g}}RT\]
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