A) 7.6 \[km{{s}^{-2}}\]
B) 7.6 \[km{{s}^{-2}}\]
C) 8.4 \[km{{s}^{-2}}\]
D) 10 \[km{{s}^{-2}}\]
Correct Answer: C
Solution :
A man of mass 50 kg is standing on an international space station. Then, distance of station from centre of earth \[r=R+h\] \[=6400+520\] [\[\because \] radius of earth R = 6400 km] \[=6920\,km\] Now, centripetal acceleration \[a=\frac{{{v}^{2}}}{r}\] \[=\frac{{{(7.6\times {{10}^{3}})}^{2}}}{6920\times {{10}^{3}}}\] \[=8.4\,\,m{{s}^{-2}}\]
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