A) 1/16
B) 1/12
C) 1/4
D) 1/32
Correct Answer: A
Solution :
\[{{T}_{1/2}}=\] 1600 yr. No = 1, N = ?, T = 6400 yr. \[T=n\times {{T}_{1/2}}\] or \[n=\frac{6400}{1600}=4\] \[N={{N}_{0}}\times {{\left( \frac{1}{2} \right)}^{n}}\] \[N=1\times {{\left( \frac{1}{2} \right)}^{4}}=\frac{1}{16}\]
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