A) 23.9
B) 27.3
C) 36.3
D) 48.3
Correct Answer: A
Solution :
Given, equivalent weight of metal == 9 Vapour density of metal chloride = 59.25 \[\therefore \] Molecular weight of metal chloride \[=2\times VD=2\times 59.25=118.50\] \[\therefore \] Valency of metal \[=\frac{mol.\text{ }wt.\text{ }of\text{ }metal\text{ }chloride}{eq.wt.\text{ }of\text{ }metal\text{ }+\text{ }35.5}\] Valency of metal \[=\frac{118.5}{9+35.5}=\frac{118.5}{44.5}=2.66\] Therefore, atomic weight of the metal = equivalent weight x valency \[=9\times 2.66=23.9\]
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