A) \[N{{i}^{2+}}\]
B) \[C{{u}^{+}}\]
C) \[Z{{n}^{2+}}\]
D) \[S{{c}^{3+}}\]
Correct Answer: A
Solution :
Elements or ions containing unpaired electrons are paramagnetic. \[Ni(28)=[Ar]3{{d}^{8}},\,4{{s}^{2}}\] \[N{{i}^{2+}}=[Ar]3{{d}^{8}},4{{s}^{0}}\] \[N{{i}^{2+}}\] stage
Because \[N{{i}^{2+}}\] have two unpaired electrons in 3d-.subshell, therefore it is paramagnetic.
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