A) \[{{O}^{2-}}\]
B) \[{{B}^{3+}}\]
C) \[L{{i}^{+}}\]
D) \[{{F}^{-}}\]
Correct Answer: A
Solution :
\[{{O}^{2-}}\] has the highest value of ionic radius and this can be explained on the basis of Z/e (Nucleus charge/No, of electron) ratio when Z/e ratio increases, the size decreases and when Z/e ratio decreases, the size increases.
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