A) \[1.58\times {{10}^{13}}\]
B) \[2.23\times {{10}^{12}}\]
C) \[2.53\times {{10}^{12}}\]
D) None of these
Correct Answer: A
Solution :
Since e/m is the charge per kg of electrons, therefore, charge on 90 kg of electrons \[=\frac{e}{m}\times 90\] \[=1.76\times {{10}^{11}}\times 90\] \[=1.58\times {{10}^{13}}C\]
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