A) 1 : 5
B) 5 : 1
C) 2 : 3
D) 6 : 1
Correct Answer: B
Solution :
\[F{{e}^{2+}}\xrightarrow{{}}F{{e}^{3+}}+{{e}^{-}}\] (Oxidation) ... (i) \[MnO_{4}^{-}+5{{e}^{-}}\xrightarrow{{}}M{{n}^{2+}}\] (Reduction) ... (ii) Eq (i) is multiply by 5 \[5F{{e}^{2+}}\xrightarrow{{}}5F{{e}^{3+}}+5{{e}^{-}}\] Then, balanced equation is \[5F{{e}^{2+}}\xrightarrow{{}}MnO_{4}^{-}\xrightarrow{{}}5F{{e}^{3+}}+M{{n}^{2+}}\] Thus, the ratio of stoichiometric coefficient of \[F{{e}^{2+}}\] and \[MnO_{4}^{-}\] is \[5:1\].
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