A) \[C{{r}_{2}}O_{7}^{2-}\]
B) \[C{{r}^{3+}}\]
C) \[Cr\,(IV)\]
D) \[C{{r}_{2}}{{O}_{3}}\]
Correct Answer: A
Solution :
In acidic medium, \[2CrO_{4}^{2-}+2{{H}^{+}}\xrightarrow{{}}C{{r}_{2}}O_{7}^{2-}+{{H}_{2}}O\] In acidic medium (in presence of \[{{H}^{+}}\]), \[CrO_{4}^{2-}\]changes to \[C{{r}_{2}}O_{7}^{2-}\] (dichromate ion).
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