| \[\underset{I}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-COOH}}\,\] |
| \[\underset{II}{\mathop{C{{H}_{3}}C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}OH}}\,\] |
 |
| \[\underset{\text{IV}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C\equiv CH}}\,\] |
A) \[I>II>III>IV\]
B) \[III>IV>II>I\]
C) \[I>III>IV>II\]
D) \[I>II>II>IV\]
Correct Answer: D
Solution :
Relative strength of organic acids A compound is acidic in nature, if its conjugate base can stabilize through resonance. Thus, phenol is more acidic while alcohol are neutral because the conjugate base of phenol \[({{C}_{6}}{{H}_{5}}{{O}^{-}})\] can be stabilised through resonance while that of alcohol cannot. Hydrogen atom attached to sp-hybridised carbon is more acidic than that of \[s{{p}^{2}}\]hybridised carbon and that of \[s{{p}^{3}}\]hybridised carbon. Thus, alkynes are more acidic than alkene and alkanes. Thus, the decreasing order of acidic strength of following acids is
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