A) \[{{R}_{o}}\]
B) \[\frac{2}{3}{{R}_{o}}\]
C) \[\frac{{{R}_{o}}}{9}\]
D) \[\frac{{{R}_{o}}}{6}\]
Correct Answer: C
Solution :
Activity \[R+{{R}_{0}}{{e}^{-\lambda t}}\] \[\frac{{{R}_{0}}}{3}={{R}_{0}}{{e}^{-9\lambda }}\,\,\,\Rightarrow \,\,\,{{e}^{-9\lambda }}=\frac{1}{3}\] ?. (i) After further \[9\,yr\,R={{\operatorname{Re}}^{-\lambda t}}=\frac{{{R}_{0}}}{3}{{e}^{-9\lambda }}\] ... (ii) From Eqs. (i) and (ii), \[R=\frac{{{R}_{0}}}{9}\]
You need to login to perform this action.
You will be redirected in
3 sec
