A) \[\frac{NA}{l}\]
B) \[\frac{N{{A}^{2}}}{l}\]
C) \[\frac{A}{l}\]
D) \[\frac{{{N}^{2}}A}{l}\]
Correct Answer: D
Solution :
Self-inductance \[L=\frac{{{\mu }_{0}}{{N}^{2}}A}{l}\] \[\Rightarrow \] \[L\propto \frac{{{N}^{2}}A}{l}\]
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