A) \[\frac{3}{2}M{{R}^{2}}\]
B) \[2M{{R}^{2}}\]
C) \[3M{{R}^{2}}\]
D) \[\frac{1}{4}M{{R}^{2}}\]
Correct Answer: A
Solution :
Since the axis of two rings are also perpendicular to each other, therefore applying the theorem of perpendicular -axes, \[I=M{{R}^{2}}+\frac{1}{2}M{{R}^{2}}\] \[=\frac{3}{2}M{{R}^{2}}\]
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