A) \[\frac{11.2}{\sqrt{2}}km/s\]
B) \[11.2\sqrt{2}km/s\]
C) \[11.2\,km/s\]
D) None of these
Correct Answer: C
Solution :
Escape velocity \[{{V}_{e}}=\sqrt{2gR}\] which is independent of the angle of projection. Therefore, the new escape velocity will be same, (ie, 11.2 km/s) irrespective of the angle, the body makes with horizontal.
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