A) 6 m/s
B) 2 m/s
C) 2.5 m/s
D) 3 m/s
Correct Answer: D
Solution :
Here, body is acting as an observer. According to the given case, let u be the velocity of th body then, \[{{v}_{1}}=v\left( \frac{v-u}{v} \right)\] and \[{{v}_{2}}=v\left( \frac{v+u}{v} \right)\] \[\therefore \] \[\Delta v={{v}_{2}}-{{v}_{1}}=v\frac{2u}{v}\] So, \[\frac{\Delta v}{v}\times 100=\frac{2u}{v}\times 100\] or \[2=\frac{2u}{v}\times 100\] or \[u=\frac{v}{100}=3\,m/s\]
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