A) \[3{{R}_{0}}\]
B) \[4{{R}_{0}}\]
C) \[5{{R}_{0}}\]
D) \[5.8{{R}_{0}}\]
Correct Answer: D
Solution :
Nuclear radius of gold \[{{(}_{79}}A{{u}^{198}})\] \[{{R}_{Ag}}={{R}_{0}}({{A}^{1/3}})\] \[={{(198)}^{1/3}}{{R}_{0}}\] \[=5.8\times {{R}_{0}}\] (where \[{{R}_{0}}1.2\times {{10}^{-15}}m=1.2\,fm\])
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