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DUMET Medical DUMET Medical Solved Paper-2008

  • question_answer
    A body cools from \[{{80}^{o}}C\] to \[{{64}^{o}}C\] in 5 min and same body cools from \[{{80}^{o}}C\] to \[{{52}^{o}}C\] in 10 min, what is the temperature of the surrounding?

    A)  \[{{24}^{o}}C\]           

    B)  \[{{28}^{o}}C\]

    C)  \[{{22}^{o}}C\]             

    D)  \[{{25}^{o}}C\]

    Correct Answer: A

    Solution :

     According to Newtons law of cooling, \[\frac{80-64}{5}=\alpha \left[ \frac{80+64}{2}-T \right]\] ... (i) and \[\frac{80-52}{10}=\alpha \left[ \frac{80+52}{2}-T \right]\] ... (ii) where T is the temperature of the surrounding. Solving Eqs. (i) and (ii), we get \[T={{24}^{o}}C\]


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