A) \[20{{\,}^{o}}C\]
B) \[\frac{100}{3}{}^{o}C\]
C) \[\frac{200}{3}{}^{o}C\]
D) None of these
Correct Answer: C
Solution :
If T be the temperature of the junction, then \[\frac{3KA(100-T)}{l}+\frac{2KA(50-T)}{l}=\frac{KA\,\,(T-0)}{l}\] \[\Rightarrow \] \[300-3T+100-2T=T\] \[\Rightarrow \] \[T=\left( \frac{200}{3} \right){{\,}^{o}}C\]You need to login to perform this action.
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