A) remains same
B) increases four times
C) reduce four times
D) None of the above
Correct Answer: A
Solution :
As per Coulombs law \[F=k\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] According to question, \[F=k\frac{({{q}_{1}}/2)\,({{q}_{2}}/2)}{{{(r/2)}^{2}}}=k\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}=F\] Thus, force between them will remain same.
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