A) 79.42 g/mol
B) 132.32 g/mol
C) 177.42 g/mol
D) 242.32 g/mol
Correct Answer: C
Solution :
Here, elevation in boiling point, \[\Delta {{T}_{b}}=0.323\,K\] weight of anthracene, \[w=0.5143\,g\] weight of chloroform \[W=35\,g\] molal elevation constant \[{{k}_{b}}=3.9\,K\,kg/mol\] \[m=\frac{{{k}_{b}}\times w\times 1000}{W\times \Delta {{T}_{b}}}=\frac{3.9\times 0.5143\times 1000}{0.323\times 35}\] \[=177.42\,g/mol\]You need to login to perform this action.
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