A) \[mgL\]
B) \[mg\frac{L}{2}\]
C) \[mg\frac{L}{3}\]
D) \[mg\frac{L}{4}\]
Correct Answer: B
Solution :
The potential energy of the rod will be according to the position of the centre of mass of the rod, which is \[\frac{L}{2}\] unit above the ground. So, potential energy of the rod \[=mg\frac{L}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
