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DUMET Medical DUMET Medical Solved Paper-2007

  • question_answer
    1 mol/L of \[{{A}_{2}}\] is present and 11% get dissociated according to the equation\[{{A}_{2}}\rightleftarrows B+C\]\[{{K}_{c}}\] for the reaction is

    A)  1.24           

    B)  1.36

    C)  1.66            

    D)  1.76

    Correct Answer: B

    Solution :

    \[{{A}_{2}}\] 11% get dissociated, i.e., 11 in 100. \[{{A}_{2}}\,\,\,\,\,\,\,\,\,\,\,\,\rightleftarrows \,\,\,\,\,\,\,\,\,B+C\] 100        0   0 initial 100-11 11 11 at equilibrium = 89 \[{{K}_{c}}=\frac{[BC][C]}{[{{A}_{2}}]}=\frac{11\times 11}{89}\] \[=1.359\approx 1.36\]


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