A) 1 : 2
B) 1 : 3
C) 2 : 3
D) 4 : 1
Correct Answer: A
Solution :
\[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\] give three ions, \[{{[Co{{(N{{H}_{3}})}_{5}}Cl]}^{2+}},2C{{l}^{-}}\], i.e., 1 : 2
You need to login to perform this action.
You will be redirected in
3 sec
