A) 100 g \[mo{{l}^{-1}}\]
B) 200 g \[mo{{l}^{-1}}\]
C) 150 g \[mo{{l}^{-1}}\]
D) 400 g \[mo{{l}^{-1}}\]
Correct Answer: B
Solution :
0.5 mole chlorine is present in 25 g of \[MC{{l}_{4}}\] mole chlorine will be present in 50 g of \[MC{{l}_{4}}\] But \[MC{{l}_{4}}\] contain 4 moles of chlorine then, molecular weight of \[MC{{l}_{4}}=4\times 50\] \[=200\,g\,mo{{l}^{-1}}\]
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