A) 3-ethyl-4-methyl hex-5-en-2-ol
B) 3-methyl-4-ethyl hex-l-en-5-ol
C) 3-ethyl-2-hydroxy-4-methyl hex-5-ene
D) none of the above
Correct Answer: A
Solution :
\[\overset{6}{\mathop{C}}\,{{H}_{2}}=\overset{5}{\mathop{C}}\,H-\overset{4}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,}}\,H-\overset{3}{\mathop{\underset{\begin{smallmatrix} | \\ {{C}_{2}}{{H}_{5}} \end{smallmatrix}}{\mathop{C}}\,}}\,H-\overset{2}{\mathop{\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,}}\,H-\overset{1}{\mathop{C}}\,{{H}_{3}}\] IUPAC Name:3-ethyl-4-methyl hex-S-en-2 -ol
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