A) 10 g \[c{{m}^{-3}}\]
B) 5g \[c{{m}^{-3}}\]
C) 15 g \[c{{m}^{-3}}\]
D) 6.5 g \[c{{m}^{-3}}\]
Correct Answer: A
Solution :
For fee radius \[=\frac{\sqrt{2}}{4}a=0.3535\,a\] Radius of Ag \[(r)=144\times {{10}^{-10}}cm\], \[a=\frac{144\times {{10}^{-10}}}{0.3535}\] \[=407.35\times {{10}^{-10}}\] Density \[(\rho )=\frac{Z\times M}{{{a}^{3}}\times {{N}_{0}}}\] \[=\frac{4\times 108}{{{(407.35\times {{10}^{-10}})}^{3}}\times 6.02\times {{10}^{23}}}\] \[=\frac{432}{6.76\times {{10}^{-23}}\times 6.02\times {{10}^{23}}}\] \[=\frac{432}{40.7}=10.6\] \[\approx 10\,g\,c{{m}^{-3}}\]
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