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DUMET Medical DUMET Medical Solved Paper-2007

  • question_answer
    what is the Q-value of the reaction \[p{{+}^{7}}Li{{\xrightarrow{{}}}^{4}}He{{+}^{4}}He\] The atomic masses of \[^{1}H{{,}^{4}}He\] and \[^{7}Li\] are 1.007825 u, 4.002603 u and 7.016004 u respectively

    A)  17.35 MeV    

    B)  18.06 MeV

    C)  177.35 MeV   

    D)  170.35 MeV

    Correct Answer: A

    Solution :

     Key Idea: The total energy released in reaction (Q) is equal to the difference in kinetic energy of the final particles and of initial particles. The total mass of the initial particles \[{{m}_{1}}1.007825+7.016004\] \[=8.023829\,\,u\] and the total mass of final particles \[{{m}_{f}}=2\times 4.002603\] \[=8.005206\,\,u\] Difference between initial and final mass of particles \[\Delta m={{m}_{i}}-{{m}_{f}}=8.023829-8.005206\] \[=0.018623\,\,u\] The Q-value is given by \[Q=(\Delta m)\,{{c}^{2}}\] \[=0.018623\times 93.15\] \[=17.35\,\,MeV\]


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