A) \[{{10}^{-8}}m\]
B) \[{{10}^{-12}}m\]
C) \[{{10}^{-16}}m\]
D) \[{{10}^{-4}}m\]
Correct Answer: D
Solution :
The product of uncertainties in the simultaneous measurement of position and momentum, energy and time, angular momentum and angular displacement is of the order of h (or h). where, \[h=\frac{h}{2\pi }\] \[\therefore \] \[\Delta p\,.\,\,\Delta x\ge h\] where \[\Delta p\] is uncertainty in the measurement of momentum of particle. The minimum uncertainty in position of particle will be \[\Delta x=\frac{h}{\Delta p}\] Here, \[\Delta p={{10}^{-30}}kg\,m/s\] \[\therefore \] \[\Delta x=\frac{1.034\times {{10}^{-34}}}{{{10}^{-30}}}\] \[={{10}^{-4}}\,m\]
You need to login to perform this action.
You will be redirected in
3 sec
