DUMET Medical DUMET Medical Solved Paper-2006

  • question_answer
    The uncertainty in momentum of an electron is \[1\times {{10}^{-5}}\]kgm/s. The uncertainty in its position will be \[(h=6.63\times {{10}^{-34}}Js)\]:

    A)  \[5.28\times {{10}^{-30}}m\]

    B)  \[5.25\times {{10}^{-28}}m\]

    C)  \[1.05\times {{10}^{-26}}m\]

    D)  \[2.715\times {{10}^{-3}}m\]

    Correct Answer: A

    Solution :

    According to Heinsenbergs uncertainty principle \[\Delta x\,\Delta p=\frac{h}{4\pi }\] \[\Delta x\] (uncertainty in position) \[=\frac{h}{4\pi \times \Delta p}\] \[=\frac{6.63\times {{10}^{-34}}}{4\times 3.14\times (1\times {{10}^{-5}})}\] \[=5.28\times {{10}^{-30}}m\].


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