A) \[N{{H}_{3}}\]
B) \[S{{F}_{4}}\]
C) \[B{{F}_{3}}\]
D) \[BC{{l}_{3}}\]
Correct Answer: A
Solution :
Ammonia is a covalent molecule. Its structure is : \[H\,_{\bullet }^{\bullet }\overset{\begin{smallmatrix} H \\ \,\bullet \,\,\bullet \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} \bullet \,\,\bullet \\ H \end{smallmatrix}}{\mathop{N}}\,\,_{\bullet }^{\bullet }}}\,\] or \[H-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{N}}\,\,_{\bullet }^{\bullet }}}\,\] According to M.O. theory, N has \[s{{p}^{3}}\]hybridisation since one pair of electrons on nitrogen remains free, the ammonia molecule gets distorted and acquires a pyramidal structure.
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