A) \[{{[W{{O}_{4}}]}^{2-}}\]
B) \[{{[Cr{{O}_{4}}]}^{2-}}\]
C) \[{{[Ce{{O}_{4}}]}^{2-}}\]
D) \[{{[Mn{{O}_{4}}]}^{2-}}\]
Correct Answer: B
Solution :
The yellow chromate ion, \[CrO_{4}^{2-}\]has a tetrahedral structure. On acidification the chromates condense to dichromate and dichromate is good oxidising agent so, \[CrO_{4}^{2-}\]is most oxidising agent among the given compounds. \[2CrO_{4}^{2-}+2{{H}^{+}}C{{r}_{2}}O_{7}^{2-}+{{H}_{2}}O\]
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