A) 1-chloro-2-ethyl-4-hydroxybut-2-ene
B) 4-hydroxy-l-chloro 2-ethyl but-2-ene
C) 4-chloro 2-ethyl but-2-en-l-ol
D) 2-ethyl 4-chloro but-2-en-l-ol
Correct Answer: C
Solution :
\[Cl-\underset{4}{\mathop{C}}\,{{H}_{2}}-H\underset{3}{\mathop{C}}\,=\overset{\begin{smallmatrix} C{{H}_{2}}C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{2}{\mathop{C}}\,}}\,-\underset{1}{\mathop{C}}\,{{H}_{2}}-OH\] because according to the order of precedence of groups ?OH named earlier than double bond and halogens.
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