A) 3.42
B) 1.62
C) 3.24
D) 1.71
Correct Answer: B
Solution :
\[\Delta {{T}_{f}}=i\times {{K}_{f}}\times \frac{n}{W}\times 1000\] i = vant Hoff factor \[{{K}_{f}}=1.86\]K /kgmol n = number of moles W = weight of solvent = 1 kg = 1000 g \[\Delta {{T}_{f}}=6\,K\] So, \[6=2\times 1.86\times \frac{n}{1000}\times 1000\] \[6=2=1.86\times n\] \[n=\frac{6}{1.86}=1.62\]
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