A) \[N{{O}^{+}}\]
B) \[C{{N}^{-}}\]
C) \[N{{O}^{-}}\]
D) \[CO\]
Correct Answer: C
Solution :
\[N{{O}^{-}}=16{{e}^{-}}=\sigma 1{{s}^{2}},\sigma *1{{s}^{2}},\sigma 2{{s}^{2}},\sigma *2{{s}^{2}}\], \[\sigma 2s_{x}^{2},\pi 2p_{y}^{2},\pi 2p_{z}^{2},\pi *2p_{y}^{1},\pi *2p_{z}^{1}\] It has two unpaired electrons so, it is paramagnetic.
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