A) C(graphite)
B) \[{{I}_{2}}(s)\]
C) \[B{{r}_{2}}(l)\]
D) red P
Correct Answer: D
Solution :
Red phosphorus has high \[\Delta {{H}_{f}}\] because it is less reactive and it is not a stable allotropic form of phosphorus. So its \[{{H}_{f}}\] would not be zero.
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