A) \[{{s}_{2}}O_{4}^{2-}\]
B) \[{{s}_{2}}O_{5}^{2-}\]
C) \[{{s}_{2}}O_{3}^{2-}\]
D) \[{{s}_{2}}O_{7}^{2-}\]
Correct Answer: D
Solution :
Key Idea: Draw the structure of all the ions to find which of them does not have S?S bond. [a] \[\underset{{{S}_{2}}O_{4}^{2-}}{\mathop{^{-}O-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}\,-{{O}^{-}}}}\,\] [b] \[\underset{{{S}_{2}}O_{5}^{2-}}{\mathop{^{-}O-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{S}}\,}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}\,-{{O}^{-}}}}\,\] [c] \[^{-}O-\overset{\begin{smallmatrix} S \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ S \end{smallmatrix}}{\mathop{S}}\,}}\,-{{O}^{-}}\] [d] \[\underset{{{S}_{2}}O_{7}^{2-}}{\mathop{^{-}O-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{S}}\,}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{S}}\,}}\,-{{O}^{-}}}}\,\] \[\therefore \,\,\,{{S}_{2}}{{O}_{7}}^{2-}\] is the correct answer.
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