A) 1
B) 2
C) 4
D) 0.001
Correct Answer: D
Solution :
Key Idea: \[{{v}_{rms}}=\sqrt{\frac{3PV}{M}}=\sqrt{\frac{3RT}{M}}\] Given, \[T={{27}^{o}}C=273+27=300\,K\] M = molar mass =? \[{{v}_{rms}}=30{{R}^{{}^{1}/{}_{2}}}\] On substituting the values we get \[30{{R}^{{}^{1}/{}_{2}}}=\sqrt{\frac{3R\times 300}{M}}\] On squaring both sides, we get \[30\times 30\times R=\frac{3\times R\times 300}{M}\] or \[M=\frac{3\times R\times 300}{30\times 30\times R}\]
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