DUMET Medical DUMET Medical Solved Paper-2005

  • question_answer
    If two substance A and B have \[{{P}_{{{A}^{o}}}}:{{P}_{{{B}^{o}}}}=1:2\]and have mole fraction in solution 1 : 2 then mol fraction of A in vapours :

    A)  0.33           

    B)  0.25

    C)  0.52           

    D)  0.2

    Correct Answer: D

    Solution :

    Key Idea: For an ideal solution of component A and B Mole fraction of component A in vapour phase \[=\frac{partial\text{ }pressure\text{ }ofA}{total\text{ }vapour\text{ }pressure}\] \[=\frac{{{P}_{A}}}{{{P}_{A}}+{{P}_{B}}}\] but \[{{P}_{A}}=P_{A}^{o}\,\,{{x}_{A}}\] and \[{{P}_{B}}=P_{B}^{o}\,\,{{x}_{B}}\] \[=\frac{P_{A}^{o}{{x}_{A}}}{A_{A}^{o}{{x}_{A}}+P_{B}^{o}{{x}_{B}}}\] Given: \[P_{A}^{o}=1,\,\,{{x}_{A}}=1\,\,\,P_{B}^{o}=2,\,\,{{x}_{B}}=2\] On substituting the values, we get Mole fraction of component A in vapour phase \[=\frac{1\times 1}{1\times 1+2\times 2}=\frac{1}{1+4}=\frac{1}{5}=0.2\]


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