A) \[AsC{{l}_{3}}\]
B) \[P{{F}_{3}}\]
C) \[SbC{{l}_{3}}\]
D) \[N{{F}_{3}}\]
Correct Answer: D
Solution :
Key Idea: During hydrolysis water forms coordinate bonds with vacant orbitals of central atom. It means central atom must have vacant orbitals. (i) \[P{{F}_{3}}\] has vacant 3d orbitals of P, \[As{{H}_{3}}\] has vacant 4d orbitals of As, \[Sb{{H}_{3}}\] has vacant Sd orbitals of Sb. So all these compounds are hydrolysed. (ii) In \[N{{F}_{3}}\], N does not have vacant d orbitals because it is member of second period. So \[N{{F}_{3}}\] cannot be hydrolysed.
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