A) \[10\mu F\]
B) \[100\mu F\]
C) \[1000\mu F\]
D) \[10000\mu F\]
Correct Answer: D
Solution :
In an R-C circuit, the product \[{{\tau }_{c}}=CR\] is the capacitive time constant of the circuit. Given, \[{{\tau }_{c}}=10\,s,\,R={{10}^{3}}\,\Omega \] \[\therefore \] \[C=\frac{{{\tau }_{c}}}{R}=\frac{10}{10}={{10}^{-2}}F\] \[\Rightarrow \] \[C=10000\,\mu F\]. Note: Smaller the product CR, the more rapidly does the charge grow on the circuit.
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