A) 1%
B) 2%
C) 1.7%
D) 0.5%
Correct Answer: B
Solution :
Maximum percentage error arises due to limit of accuracy of the measured value. From Joules law of heating, the power change due to current (i), through resistor (R) is given by \[P={{i}^{2}}R\] Taking log on both sides, we get \[\log P=2\log i+\log R\] Taking partial differentiation, we have \[\frac{\Delta \,P}{P}\times 100=2\frac{\Delta \,i}{i}\times 100+\frac{\Delta \,R}{R}\times 100\] Given, \[\frac{\Delta \,i}{i}=1,\frac{\Delta \,R}{R}=0\] \[\therefore \] \[\frac{\Delta \,P}{P}\times 100=2\times 1%\] \[=2%\]
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