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DUMET Medical DUMET Medical Solved Paper-2005

  • question_answer
     50 tuning forks are arranged in increasing order of their frequencies such that each gives 4 beats/s with its previous tuning fork. If the frequency of the last fork is octave of the First, then the frequency of the first tuning fork is :

    A)  200 Hz       

    B)  204 Hz

    C)  196 Hz       

    D)  none of these

    Correct Answer: C

    Solution :

     Number of beats/s (beat frequency) is equal to difference of the frequencies of sound sources. Since, each tuning fork gives 4 beats/s with its previous tuning fork, we have \[{{f}_{n}}={{f}_{1}}+(n-1)\,d\] \[\Rightarrow \] \[2\,f=f+(50-1)\times 4\] \[\Rightarrow \] \[f=49\times 4=196\,Hz\].


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