A) -0.75, 1.25
B) -0.75, 1.0
C) -0.75, 0.6
D) -3.1, 25
Correct Answer: A
Solution :
Average formal charge on each of the oxygen atom is calculated as follows : (i) Total number of electrons present in valence shell of phosphate ion = 5 + 8 = 13 (ii) Total number of electrons involved in bond formation = 13 - .3 = 10 (i) Number of bonds in \[PO_{4}^{3-}\] ion \[=\frac{10}{2}=5\] (ii) Average P?O bond order \[=\frac{5}{4}=1.25\] (iii) Average formal charge on each O atom \[=\frac{total\text{ }charge}{total\text{ }entity\text{ }ofOatom}\] \[=-\frac{3}{4}=-0.75\]
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