A) \[366\,\Omega \]
B) \[69\,\Omega \]
C) \[266\,\Omega \]
D) \[109\,\Omega \]
Correct Answer: C
Solution :
It \[{{R}_{t}}\] be resistance att \[^{o}C\] and \[{{R}_{0}}\] be at \[{{0}^{o}}C\], and a be temperature coefficient of resistance, then \[{{R}_{t}}={{R}_{0}}\,(1+\alpha \,t)\] \[\therefore {{R}_{150}}={{R}_{0}}\,(1+150\times 0.0045)=133\,\,\Omega \] ... (i) and \[\therefore {{R}_{0}}\,\,(1+500\times 0.0045)={{R}_{t}}\] ... (ii) Dividing Eq. (ii) by (i), we get \[\frac{{{R}_{t}}}{133}=\frac{3.25}{1.675}\approx 2\,\Omega \] \[\Rightarrow \] \[{{R}_{t}}=2\times 133\] \[{{R}_{t}}=266\,\,\Omega \]
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