DUMET Medical DUMET Medical Solved Paper-2004

  • question_answer
    One mole of NaCI (s) on melting absorbed 30.5 kJ of heat and its entropy is increased by 28.8 \[J{{K}^{-1}}\]. The melting point of NaCI is:

    A)  1059 K        

    B)  30.5 K

    C)  28.8 K        

    D)  28800 K

    Correct Answer: A

    Solution :

    Key Idea: Use the following formula to solve the problem. \[\Delta S=\frac{\Delta H}{T}\] Given, \[\Delta S=\] change in entropy \[=28.8\,J{{K}^{-1}}\] \[=28.8\times {{10}^{-3}}kJ\,{{K}^{-1}}\] \[\Delta H=\] change in enthalpy \[=30.5\,kJ\,mo{{l}^{-1}}\] r = temperature \[\therefore \] \[28.8\times {{10}^{-3}}=\frac{30.5}{T}\] or \[T=\frac{30.5}{28.8\times {{10}^{-3}}}\] \[=1.059\times {{10}^{3}}\] = 1059 K


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