A) \[2.73\times {{10}^{-24}}\]
B) \[2.42\times {{10}^{-10}}\]
C) \[242.2\times {{10}^{10}}\]
D) none of these
Correct Answer: B
Solution :
Key Idea: Use the following formula to find the answer: \[\lambda =\frac{h}{p}\] where, \[\lambda =\] de-Broglie wavelength \[h=\] Plancks constant \[=6.626\times {{10}^{-34}}Js\] \[p=mv\] where \[m=9.11\times {{10}^{-31}}kg\] \[v=\frac{1}{100}\times (3\times {{10}^{8}})m{{s}^{-1}})\] \[=3\times {{10}^{6}}m{{s}^{-1}}\] \[\therefore \] \[\lambda =\frac{6.626\times {{10}^{-34}}}{9.11\times {{10}^{-31}}\times 3\times {{10}^{6}}}\] \[=2.424\times {{10}^{-10}}\]
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